**How Many Iron Atoms Are Contained In 354G Of Iron**. 354 g fe x 1 mole fe/55.85 g fe x 6.02×10^23 atoms fe/mole fe = 3.82×10^24 atoms of iron Enter your answer in the provided box.

A) 2.62 1025 fe atoms b) 2.13 1026 fe atoms c) 4.69. 354 g fe x 1 mole fe/55.85 g fe x 6.02×10^23 atoms fe/mole fe = 3.82×10^24 atoms of iron Calculate the number of iron atoms in a piece of iron weighing `2.8 g` (atomic mass of iron `= 56 u`).

### Metallic Iron Crystallizes In A Cubic Lattice.

Now 1 mole of any element contains 6.023x 10 23 number of atoms which is called avogadro number. Solution for how many iron atoms are contained in 354 g of iron? This value should be given otherwise needs to be memorised as iron is very common metal.

### A) 2.62 1025 Fe Atoms B) 2.13 1026 Fe Atoms C) 4.69.

Convert g to mols then mols to atoms using avogdro’s number 1g fe x 6.023 x 10^23 atoms fe/55.8 g fe = 1.08 x 10^22 atoms fe 100% (46 ratings) first of all you have to know the molar mass of iron which is 55.845 g/mole. That means 55.845 g of iron contains 6.023x 10 23 atoms.

### Enter Your Answer In The Provided Box.

354 g fe x 1 mole fe/55.85 g fe x 6.02×10^23 atoms fe/mole fe = 3.82×10^24 atoms of iron Calculate the number of iron atoms in a piece of iron weighing `2.8 g` (atomic mass of iron `= 56 u`). How many iron atoms are contained in 354 g of iron?

### The Density Of Iron Is 7.87 G/Cm3.

How many iron atoms are contained in. Solution for how many iron atoms are contained in 354 g of iron o 3.82 x 1024 fe atoms o 4.69 x 1024 fe atoms o 9.50 x 1022 fe atoms. 354 g fe x 1 mole fe/55.85 g fe x 6.02×10^23 atoms fe/mole fe = 3.82×10^24 atoms of iron

### In Total There Are 2.8·10 26 Electrons.

100% (2 ratings) given mass of iron = 354g molecular mass of iron = 55. How many iron atoms are contained in 354 g of iron? The unit cell edge length is 287 pm.